Total number of nodes for any orbital = $n - 1$
Angular nodes = $l$, Radial nodes = $n - l - 1$
For 4f orbital: $n = 4$, $l = 3$
So, radial nodes = $4 - 3 - 1 = 0$
Angular nodes = $l = 3$
Therefore, the number of radial and angular nodes are 0 and 3 respectively.