Using Raoult’s Law for the vapor pressure of a solution: \[ P_{\text{solution}} = P_{\text{solvent}} \times X_{\text{solvent}} \] Where \(P_{\text{solution}}\) is the vapor pressure of the solution, \(P_{\text{solvent}}\) is the vapor pressure of the pure solvent, and \(X_{\text{solvent}}\) is the mole fraction of the solvent. Given that the solute is non-volatile, the mole fraction of the solvent is approximately \(1 - \text{molality of the solution}\), which leads to a slight reduction in vapor pressure. The vapor pressure is then given by \(0.982x\).