The second shell (L-shell) can hold a maximum of 8 electrons. Assuming the second shell is completely filled for an element progressing to the third shell, it has 8 electrons.
Number of electrons in the third shell = 25% of electrons in the second shell
Number of electrons in the third shell = 0.25 \(\times\) 8 = 2 electrons.
The electronic configuration of element 'M' is:
First shell (K-shell): 2 electrons
Second shell (L-shell): 8 electrons
Third shell (M-shell): 2 electrons
So, the electronic configuration is 2, 8, 2.
The atomic number of element 'M' = Total number of electrons = 2 + 8 + 2 = 12.
The element with atomic number 12 is Magnesium (Mg).
Electronic configurations of the given options:
% Option
(a) Sodium (Na, Z=11): 2, 8, 1
% Option
(b) Magnesium (Mg, Z=12): 2, 8, 2
% Option
(c) Aluminium (Al, Z=13): 2, 8, 3
% Option
(d) Calcium (Ca, Z=20): 2, 8, 8, 2
Element 'M' is Magnesium.
\[ \boxed{\text{Magnesium}} \]