The antibonding electrons are those in the \( \sigma^ \) and \( \pi^ \) molecular orbitals. For each species:
- \( N_2^+ \) has 15 electrons, which means 6 antibonding electrons.
- \( O_2^+ \) has 15 electrons, resulting in 5 antibonding electrons.
- \( O_2^- \) has 17 electrons, resulting in 4 antibonding electrons.
Thus, the number of antibonding electrons in \( N_2^+ \), \( O_2^+ \), and \( O_2^- \) is 4, 5, 6.
Thus, the correct answer is Option 4.