We are asked to find the number of 5-digit odd numbers greater than 40,000 that can be formed using the digits \( 3, 4, 5, 6, 7, 0 \), such that at least one digit is repeated. To form a 5-digit number, we need to ensure that:
1. The number is odd, meaning the last digit must be one of \( 3, 5, 7 \).
2. The number must be greater than 40,000, so the first digit must be at least 4, i.e., \( 4, 5, 6, 7 \).
3. At least one digit must be repeated.
5
Step 1: Total number of 5-digit odd numbers greater than 40,000:
The first digit can be \( 4, 5, 6, \) or \( 7 \) (4 choices). The second, third, and fourth digits can be \( 0, 3, 4, 5, 6, 7 \) (6 choices each). The last digit can be \( 3, 5, 7 \) (3 choices). Thus, the total number of such 5-digit numbers is: \[ 4 \times 6 \times 6 \times 6 \times 3 = 2592. \]
Step 2: Now, we subtract the number of 5-digit odd numbers where no digits are repeated. The first digit can be chosen from \( 4, 5, 6, 7 \) (4 choices). The second digit can be chosen from \( 0, 3, 4, 5, 6, 7 \) excluding the first digit (5 choices).
The third digit can be chosen from the remaining 4 digits (4 choices). The fourth digit can be chosen from the remaining 3 digits (3 choices). The last digit can be chosen from \( 3, 5, 7 \), excluding the digits used already (2 choices). Thus, the number of such numbers is: \[ 4 \times 5 \times 4 \times 3 \times 2 = 480. \]
Step 3: Finally, subtract the number of numbers with no repeated digits from the total number of numbers: \[ 2592 - 480 = 2112. \] Therefore, the number of 5-digit odd numbers greater than 40,000, where at least one digit is repeated, is 2352.
Let \(S=\left\{ z\in\mathbb{C}:\left|\frac{z-6i}{z-2i}\right|=1 \text{ and } \left|\frac{z-8+2i}{z+2i}\right|=\frac{3}{5} \right\}.\)
Then $\sum_{z\in S}|z|^2$ is equal to
Which of the following are ambident nucleophiles?
[A.] CN$^{\,-}$
[B.] CH$_{3}$COO$^{\,-}$
[C.] NO$_{2}^{\,-}$
[D.] CH$_{3}$O$^{\,-}$
[E.] NH$_{3}$
Identify the anomers from the following.

The standard Gibbs free energy change \( \Delta G^\circ \) of a cell reaction is \(-301 { kJ/mol}\). What is \( E^\circ \) in volts?
(Given: \( F = 96500 { C/mol}\), \( n = 2 \))