Question:
The motion of a particle of mass \( m \) is described by
\( y = ut + g t^2 \). The force acting on the particle will be
The motion of a particle of mass \( m \) is described by
\( y = ut + g t^2 \). The force acting on the particle will be
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Differentiate position-time equation twice to find acceleration, then apply \( F = ma \).
Updated On: Apr 23, 2025
- zero
- \( 4mg \)
- \( 3mg \)
- \( 2mg \)
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The Correct Option is D
Solution and Explanation
Given:
\[
y = ut + gt^2
\Rightarrow \text{Acceleration} = \frac{d^2 y}{dt^2} = 2g
\]
Now using Newton’s second law:
\[
F = m a = m \cdot 2g = 2mg
\]
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