A | B |
Weak electrolyte | Weak electrolyte |
A | B |
Strong electrolyte | strong electrolyte |
A | B |
Weak electrolyte | strong electrolyte |
A | B |
Strong electrolyte | Weak electrolyte |
Explanation: The graph shows the variation of molar conductivity (\( \Lambda_m \)) with \( C^{1/2} \), the square root of concentration:
Therefore:
Electrolyte A → Weak electrolyte, Electrolyte B → Strong electrolyte.
Final Answer is Option (3).
If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:
[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.