The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly :
- 1.5 eV
- 13.6 eV
- 1.9 eV
- 12.1 eV
The Correct Option is D
Solution and Explanation
For the hydrogen atom, the transition from \(n = 1\) to \(n = 3\) gives the radiation in the Balmer series:
\[ \Delta E = 12.1 \, \text{eV} \]
Thus, the correct answer is Option (4).
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