Question

The median class of the following table will be:

• A. 0 - 10
• B. 10 - 20
• C. 20 - 30
• D. 30 - 40

Hint:

To find the median class, look for the class where the cumulative frequency exceeds half of the total frequency.

Answer 1

The Correct Option is C

We are given the following frequency distribution:

The total frequency \( N \) is the sum of all frequencies: \[ N = 7 + 5 + 16 + 12 + 2 = 42 \] The cumulative frequency is: \[ CF_1 = 7, \quad CF_2 = 7 + 5 = 12, \quad CF_3 = 12 + 16 = 28, \quad CF_4 = 28 + 12 = 40, \quad CF_5 = 40 + 2 = 42 \] The median class is the class interval whose cumulative frequency is greater than or equal to \( \frac{N}{2} \). Here, \( \frac{42}{2} = 21 \), and the cumulative frequency just greater than 21 is 28, which corresponds to the class interval \( 20 - 30 \).
Step 1: Conclusion.
Thus, the median class is \( 20 - 30 \).