Question

The median class of the following frequency distribution will be:

• A. 40-50
• B. 30-40
• C. 20-30
• D. 10-20

Hint:

To find the median class, calculate the cumulative frequency and identify the class where the cumulative frequency first exceeds \( \frac{N}{2} \).

Answer 1

The Correct Option is C

To find the median class, we first calculate the cumulative frequencies: \[ \text{Class interval:} \quad 0-10, 10-20, 20-30, 30-40, 40-50 \] \[ \text{Frequency:} \quad 4, 5, 13, 20, 8 \] Now, compute the cumulative frequency: \[ \text{Cumulative frequency:} \quad 4, 9, 22, 42, 50 \] The total frequency \( N \) is 50.
Step 1: Find the median position.
The median position is given by: \[ \frac{N}{2} = \frac{50}{2} = 25 \]
Step 2: Find the median class.
The cumulative frequency just greater than or equal to 25 is 42, which corresponds to the class interval \( 20-30 \). Thus, the median class is \( 20-30 \).