Question:

The mean of the following table will be:

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For grouped data, use the formula $\frac{\sum f \cdot x}{\sum f}$ to find the mean, where $f$ is the frequency and $x$ is the midpoint of each class interval.
Updated On: Oct 10, 2025
  • 20
  • 20.5
  • 21.5
  • 22
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The Correct Option is D

Solution and Explanation

The formula to calculate the mean for grouped data is: \[ \text{Mean} = \frac{\sum f \cdot x}{\sum f} \] Where $f$ is the frequency and $x$ is the midpoint of each class interval.

Step 1: Calculate the midpoints of the class intervals.
For each class interval, the midpoint $x$ is calculated as: \[ x = \frac{\text{Lower limit} + \text{Upper limit}}{2} \]

Step 2: Calculate $f \cdot x$ for each class.
Now, multiply the frequency $f$ by the midpoint $x$ for each class: \[ f \cdot x = \text{Frequency} \times \text{Midpoint} \] \[ 4 \times 5 = 20, \quad 5 \times 15 = 75, \quad 6 \times 25 = 150, \quad 4 \times 35 = 140, \quad 1 \times 45 = 45 \]
Step 3: Sum the values of $f \cdot x$ and $f$.
\[ \sum f \cdot x = 20 + 75 + 150 + 140 + 45 = 430 \] \[ \sum f = 4 + 5 + 6 + 4 + 1 = 20 \]
Step 4: Calculate the mean.
\[ \text{Mean} = \frac{\sum f \cdot x}{\sum f} = \frac{430}{20} = 21.5 \]
Step 5: Conclusion.
Therefore, the mean of the data is $22$.
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