The reaction for the deposition of zinc is as follows:
Zn2+ + 2e- → Zn
Using the formula for electrolysis:
W = \( \frac{Z \times i \times t}{F} \)
where
Calculating the mass of zinc:
W = \( \frac{65.4}{2 \times 96500} \times 0.015 \times 15 \times 60 \)
W = 45.75 $\times$ 10-4 g
Since the answer can be approximated, we also consider 46 $\times$ 10-4 g.
So, the correct answer is: 45.75 or 46
Step 1: Use Faraday’s law of electrolysis.
According to Faraday’s first law: \[ m = \frac{E \, I \, t}{F} \] where \( m \) = mass of substance deposited (in g), \( E \) = equivalent weight of substance, \( I \) = current (A), \( t \) = time (s), \( F \) = Faraday’s constant \( = 96500\,\text{C/mol} \).
For Zn²⁺ + 2e⁻ → Zn, number of electrons \( n = 2 \). \[ E = \frac{\text{Atomic mass}}{n} = \frac{65.4}{2} = 32.7 \]
\[ I = 0.015\,\text{A}, \quad t = 15\,\text{min} = 15 \times 60 = 900\,\text{s} \] \[ m = \frac{32.7 \times 0.015 \times 900}{96500} \]
\[ m = \frac{32.7 \times 13.5}{96500} = \frac{441.45}{96500} = 0.00457\,\text{g} \] \[ m = 4.575 \times 10^{-3}\,\text{g} = 45.75 \times 10^{-4}\,\text{g} \]
\[ \boxed{45.75 \times 10^{-4}\,\text{g}} \]

Let \( C_{t-1} = 28, C_t = 56 \) and \( C_{t+1} = 70 \). Let \( A(4 \cos t, 4 \sin t), B(2 \sin t, -2 \cos t) \text{ and } C(3r - n_1, r^2 - n - 1) \) be the vertices of a triangle ABC, where \( t \) is a parameter. If \( (3x - 1)^2 + (3y)^2 = \alpha \) is the locus of the centroid of triangle ABC, then \( \alpha \) equals:
Designate whether each of the following compounds is aromatic or not aromatic.
