In this reaction, an alkene side chain attached to the benzene ring reacts with excess con centrated HBr.
The mechanism involves the following steps:
Step 1. The double bond in the alkene reacts with HBr to form a carbocation intermediate.
Step 2. Due to excess HBr, the benzyl carbo cation rearranges to a more stable form.
Step 3. The addition of Br takes place, resulting in the formation of the major product, which is the bromo-substituted alkane on the benzene ring.
Thus, the major product is:
Number of \( ^1H \) NMR signals observed for the following compound is .............
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: