In this reaction, an alkene side chain attached to the benzene ring reacts with excess con centrated HBr.
The mechanism involves the following steps:
Step 1. The double bond in the alkene reacts with HBr to form a carbocation intermediate.
Step 2. Due to excess HBr, the benzyl carbo cation rearranges to a more stable form.
Step 3. The addition of Br takes place, resulting in the formation of the major product, which is the bromo-substituted alkane on the benzene ring.
Thus, the major product is:
Match the following:
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}
The equilibrium constant for decomposition of $ H_2O $ (g) $ H_2O(g) \rightleftharpoons H_2(g) + \frac{1}{2} O_2(g) \quad (\Delta G^\circ = 92.34 \, \text{kJ mol}^{-1}) $ is $ 8.0 \times 10^{-3} $ at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ($ \alpha $) of water is _____ $\times 10^{-2}$ (nearest integer value). [Assume $ \alpha $ is negligible with respect to 1]