Question:
The major product(P) in the following reaction is
The major product(P) in the following reaction is
Updated On: Mar 23, 2025
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
In this reaction, an alkene side chain attached to the benzene ring reacts with excess con centrated HBr.
The mechanism involves the following steps:
Step 1. The double bond in the alkene reacts with HBr to form a carbocation intermediate.
Step 2. Due to excess HBr, the benzyl carbo cation rearranges to a more stable form.
Step 3. The addition of Br takes place, resulting in the formation of the major product, which is the bromo-substituted alkane on the benzene ring.
Thus, the major product is:
Was this answer helpful?
1
0
Top Questions on Organic Chemistry- Some Basic Principles and Techniques
- Match List I with List II
List-I
(Complex)List-II
(Type of isomerism)(A) [Co(NH3)5(NO2)]Cl2 (I) Solvate isomerism (B) [Co(NH3)5(SO4)]Br (II) Linkage isomerism (C) [Co(NH3)6] [Cr(CN)6] (III) Ionization isomerism (D) [Co(H2O)6]Cl3 (IV) Coordination isomerism
Choose the correct answer from the options given below:- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- Match List I with List II
List-I
(Conversion)List-II
(Shape/geometry)(A) 1 mol of H2O to O2 (I) 3F (B) 1 mol of MnO-4 to Mn2+ (II) 2F (C) 1.5 mol of Ca from molten CaCl2 (III) 1F (D) 1 mol of FeO to Fe2O3 (IV) 5F
Choose the correct answer from the options given below:- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- The most stable carbocation among the following is:
- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- The compound that will undergo SN1 reaction with the fastest rate is
- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- Given below are two statements :
Statement I : The boiling point of three isomeric pentanes follows the order
n-pentane > isopentane > neopentane
Statement II : When branching increases, the molecule attains a shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point.
In the light of the above statements, choose the most appropriate answer from the options given below :- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
View More Questions
Questions Asked in JEE Main exam
- If \( \sin x + \sin^2 x = 1 \), \( x \in \left(0, \frac{\pi}{2} \right) \), then the expression \[ (\cos^2 x + \tan^2 x) + 3(\cos^4 x + \tan^4 x + \cos^4 x + \tan^4 x) + (\cos^6 x + \tan^6 x) \] is equal to:
- JEE Main - 2025
- Trigonometric Identities
- The sum of the squares of all the roots of the equation \( x^2 + [2x - 3] - 4 = 0 \) is:
- JEE Main - 2025
- Quadratic Equations
- Let ABCD be a trapezium whose vertices lie on the parabola \( y^2 = 4x \). Let the sides AD and BC of the trapezium be parallel to the y-axis. If the diagonal AC is of length \( \frac{25}{4} \) and it passes through the point \( (1, 0) \), then the area of ABCD is:
- JEE Main - 2025
- Coordinate Geometry
- A molecule (P) on treatment with acid undergoes rearrangement and gives (Q). (Q) on ozonolysis followed by reflux under alkaline condition gives (R). The structure of (R) is given below. The structure of (P) is:
- JEE Main - 2025
- Organic Chemistry
- The product B formed in the following reaction sequence is: \[ {C}_6{H}_5{CN} \xrightarrow{{HCl}} (A) \xrightarrow{{AgCN}} (B) \]
- JEE Main - 2025
- Organic Chemistry
View More Questions