Benzene diazonium chloride (\({C_6H_5N_2Cl}\)) is a reactive compound used in various transformations. Its reaction with ethanol involves a reduction process.
Step 1: Reaction mechanism
Ethanol (\({C_2H_5OH}\)) acts as a mild reducing agent, converting the diazonium group (\({-N_2^+}\)) to nitrogen gas and forming benzene: \[ {C_6H_5N_2^+ + C_2H_5OH -> C_6H_6 + N_2 + CH_3CHO + H^+} \] Ethanol is oxidized to acetaldehyde (\({CH_3CHO}\)), and the diazonium ion releases \({N_2}\), yielding benzene (\({C_6H_6}\)).
Step 2: Analyze options
- (A) Aniline (\({C_6H_5NH_2}\)): Formed by strong reduction (e.g., \({Sn/HCl}\)), not ethanol.
- (B) Phenetole (\({C_6H_5OC_2H_5}\)): Requires phenol and ethanol under different conditions.
- (C) Benzene (\({C_6H_6}\)): Correct, as ethanol reduces the diazonium ion.
- (D) p-Chloro phenol: Involves chlorination and phenolic conditions, not relevant.
Step 3: Conclusion
The product is benzene, matching option (C).
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____. 
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
If 0.01 mol of $\mathrm{P_4O_{10}}$ is removed from 0.1 mol, then the remaining molecules of $\mathrm{P_4O_{10}}$ will be: