Benzene diazonium chloride (\({C_6H_5N_2Cl}\)) is a reactive compound used in various transformations. Its reaction with ethanol involves a reduction process.
Step 1: Reaction mechanism
Ethanol (\({C_2H_5OH}\)) acts as a mild reducing agent, converting the diazonium group (\({-N_2^+}\)) to nitrogen gas and forming benzene: \[ {C_6H_5N_2^+ + C_2H_5OH -> C_6H_6 + N_2 + CH_3CHO + H^+} \] Ethanol is oxidized to acetaldehyde (\({CH_3CHO}\)), and the diazonium ion releases \({N_2}\), yielding benzene (\({C_6H_6}\)).
Step 2: Analyze options
- (A) Aniline (\({C_6H_5NH_2}\)): Formed by strong reduction (e.g., \({Sn/HCl}\)), not ethanol.
- (B) Phenetole (\({C_6H_5OC_2H_5}\)): Requires phenol and ethanol under different conditions.
- (C) Benzene (\({C_6H_6}\)): Correct, as ethanol reduces the diazonium ion.
- (D) p-Chloro phenol: Involves chlorination and phenolic conditions, not relevant.
Step 3: Conclusion
The product is benzene, matching option (C).
If 0.01 mol of $\mathrm{P_4O_{10}}$ is removed from 0.1 mol, then the remaining molecules of $\mathrm{P_4O_{10}}$ will be:
Ratio of time required for 99% completion vs 90% completion of a first order reaction is: