




Step-by-step Solution:
The reaction in question involves the use of a reagent BrCH_2 CO_2Et with zinc (Zn). This type of reaction is commonly known as the Reformatsky reaction. Let's go through the steps to understand the formation of the major product:
The first step is the oxidative addition of zinc into the carbon-bromine bond, forming an organozinc compound:
BrCH_2CO_2Et + Zn \rightarrow ZnBrCH_2CO_2Et
This step involves the nucleophilic addition of the organozinc species to the carbonyl compound, followed by hydrolysis to give the final product.
This image shows the structure of a β-hydroxy ester, which is the expected product from the Reformatsky reaction process.
Reasoning for Correct Option:
Hence, the correct answer is the β-hydroxy ester, represented by the selected image option.
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