The major product of the following reaction is:
The reaction between propanal and formaldehyde in alkaline medium proceeds via the crossed Cannizzaro mechanism:
Reaction Mechanism:
1. Nucleophilic attack by hydroxide on formaldehyde (more reactive carbonyl)
2. Hydride transfer to propanal
3. Formaldehyde gets oxidized to formate ion
4. Propanal gets reduced to propanol
Chemical Equations:
CH3CH2CHO + HCHO + NaOH →
CH3CH2CH2OH + HCOONa
Key Points:
- Formaldehyde always oxidizes to formate in Cannizzaro reactions
- The other aldehyde (propanal) reduces to alcohol
- No alpha-hydrogen required for this disproportionation
The major organic product is propanol (CH3CH2CH2OH).
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
A hydrocarbon which does not belong to the same homologous series of carbon compounds is
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: