Step 1: Bromination of the amino group on the aromatic ring will lead to the formation of a bromo-phenyl group at the para position with respect to the amino group.
Step 2: The reaction with aqueous KOH will induce nucleophilic substitution, replacing the bromine with a hydrogen atom.
Therefore, the final product is Ph–CH2–H (option B).
Thus, the correct answer is B
The correct option is (B) :