Question:
The length of a seconds pendulum if it is placed at height \(2R\) from the surface of the earth (R: radius of earth) is \(\frac{10}{xπ^2}\) \(m\). Find \(x\)
The length of a seconds pendulum if it is placed at height \(2R\) from the surface of the earth (R: radius of earth) is \(\frac{10}{xπ^2}\) \(m\). Find \(x\)
Updated On: Feb 2, 2024
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The Correct Answer is : 9
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Concepts Used:
Energy In Simple Harmonic Motion
We can note there involves a continuous interchange of potential and kinetic energy in a simple harmonic motion. The system that performs simple harmonic motion is called the harmonic oscillator.
Case 1: When the potential energy is zero, and the kinetic energy is a maximum at the equilibrium point where maximum displacement takes place.
Case 2: When the potential energy is maximum, and the kinetic energy is zero, at a maximum displacement point from the equilibrium point.
Case 3: The motion of the oscillating body has different values of potential and kinetic energy at other points.