Question:

The Laplace transform of \( \frac{s}{s^2 + a^2} \) is:

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For Laplace transforms, remember that: \( \mathcal{L} \{ \cos(at) \} = \frac{s}{s^2 + a^2} \),
\( \mathcal{L} \{ \sin(at) \} = \frac{a}{s^2 + a^2} \).
These standard transforms help identify the inverse transforms more quickly.
Updated On: Apr 14, 2025
  • \( \cos(at) \)
  • \( \sin(at) \)
  • \( \sinh(at) \)
  • \( \cosh(at) \)
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The Correct Option is A

Solution and Explanation

The Laplace transform of a function \( f(t) \) is defined as: \[ \mathcal{L} \{ f(t) \} = \int_0^\infty e^{-st} f(t) \, dt. \] We are asked to find the function whose Laplace transform is \( \frac{s}{s^2 + a^2} \). From standard Laplace transforms, we know that the Laplace transform of \( \cos(at) \) is: \[ \mathcal{L} \{ \cos(at) \} = \frac{s}{s^2 + a^2}. \] Thus, the given expression \( \frac{s}{s^2 + a^2} \) corresponds to the Laplace transform of \( \cos(at) \).
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