Question:

A cylindrical concrete silo of 6 m internal diameter and 24 m height is filled with rough rice having a bulk density of 635 kg/m\(^3\). The angle of friction between the concrete wall and rough rice is 30°. The ratio between lateral and vertical pressure is 0.4. The ratio of lateral pressure at 10 m depth to the 5 m depth is _________. (Rounded off to 2 decimal places)

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To calculate the ratio of lateral pressure at different depths, first calculate the vertical pressure at each depth and then use the given ratio to find the corresponding lateral pressures.
Updated On: Apr 14, 2025
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Solution and Explanation

We are given the following parameters:
Diameter of the silo \( D = 6 \, {m} \),
Height of the silo \( H = 24 \, {m} \),
Bulk density of rice \( \rho = 635 \, {kg/m}^3 \),
Angle of friction between concrete and rice \( \theta = 30^\circ \),
The ratio of lateral pressure to vertical pressure \( \frac{P_{{lateral}}}{P_{{vertical}}} = 0.4 \).
Step 1: Calculate the vertical pressure at different depths
The vertical pressure at a given depth in the silo is calculated using the formula: \[ P_{{vertical}} = \rho g h \] Where:
\( \rho \) is the bulk density of the rice,
\( g \) is the acceleration due to gravity (approximately \( 9.81 \, {m/s}^2 \)),
\( h \) is the depth.
At a depth of 5 m: \[ P_{{vertical, 5m}} = 635 \times 9.81 \times 5 = 31241.75 \, {Pa} \] At a depth of 10 m: \[ P_{{vertical, 10m}} = 635 \times 9.81 \times 10 = 62483.5 \, {Pa} \] Step 2: Calculate the lateral pressure at different depths
The lateral pressure is related to the vertical pressure by the ratio given: \[ P_{{lateral}} = 0.4 \times P_{{vertical}} \] At a depth of 5 m: \[ P_{{lateral, 5m}} = 0.4 \times 31241.75 = 12496.7 \, {Pa} \] At a depth of 10 m: \[ P_{{lateral, 10m}} = 0.4 \times 62483.5 = 24993.4 \, {Pa} \] Step 3: Calculate the ratio of lateral pressure at 10 m depth to the 5 m depth
Now, calculate the ratio of lateral pressure at 10 m depth to the lateral pressure at 5 m depth: \[ {Ratio} = \frac{P_{{lateral, 10m}}}{P_{{lateral, 5m}}} = \frac{24993.4}{12496.7} = 1.41 \] Thus, the ratio of lateral pressure at 10 m depth to the 5 m depth is 1.41.
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