The Ksp for bismuth sulphide (Bi 2 S 3 ) is 1.08 × 10 –73. The solubility of Bi 2 S 3 in mol L –1 at 298 K is

The correct option is(A): 1.0 × 10 –15 \(Bi_2S3⇋2Bi^3+2s+3s^2-3s\) K sp = (2s) 2 (3s) 3 = 108s 5 108s 5 = 108 × 10 –75 s = 1.0 × 10 –15 mol/L

Question:

The Ksp for bismuth sulphide (Bi₂S₃) is 1.08 × 10^–73. The solubility of Bi₂S₃ in mol L^–1 at 298 K is

Updated On: Mar 21, 2025

1.0 × 10^–15
2.7 × 10^–12
3.2 × 10^–10
4.2 × 10^–8

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The Correct Option is A

Solution and Explanation

The correct option is(A): 1.0 × 10^–15

\(Bi_2S3⇋2Bi^3+2s+3s^2-3s\)

K_sp = (2s)²(3s)³ = 108s⁵

108s⁵ = 108 × 10^–75

s = 1.0 × 10^–15 mol/L

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The Ksp for bismuth sulphide (Bi2S3) is 1.08 × 10–73. The solubility of Bi2S3 in mol L–1 at 298 K is