The compound shown is a monosaccharide with an aldehyde group (-CHO) and multiple hydroxyl (-OH) groups. When treated with Br$_2$ water, it is not oxidized to a dicarboxylic acid but rather forms a monocarboxylic acid, making option (1) incorrect.
Statement (2) is correct: Despite having a –CHO group, certain sugars like glucose do not respond to Schiff’s test.
Statement (3) is correct: There are 4 chiral (asymmetric) carbon atoms present in the structure.
Statement (4) is correct: The compound can exist in equilibrium with two other cyclic forms, $\alpha$-D-glucose and $\beta$-D-glucose.
Complete the following equation :
Write the products of the following reactions:
Predict the major product $ P $ in the following sequence of reactions:
(i) HBr, benzoyl peroxide
(ii) KCN
(iii) Na(Hg), $C_{2}H_{5}OH$