The structures of cis-2-butene and trans-2-butene are as follows:
cis-2-butene: \( \text{CH}_3 - \text{CH} = \text{CH} - \text{CH}_3 \) (Polar)
trans-2-butene: \( \text{H} - \text{CH} = \text{CH} - \text{CH}_3 \) (Non-Polar)
Cis-but-2-ene has a higher dipole moment than trans-but-2-ene due to the arrangement of the substituent groups. The cis configuration results in a net dipole moment, while the trans configuration cancels out the dipole due to symmetry.
Complete the following reactions by writing the structure of the main products:
Let $ f(x) = \begin{cases} (1+ax)^{1/x} & , x<0 \\1+b & , x = 0 \\\frac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2} & , x>0 \end{cases} $ be continuous at x = 0. Then $ e^a bc $ is equal to
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)