The hybridization of P exhibited in \(PF_5\) is \(sp_xd_y\). The value of y is _____ .
Correct Answer: 1
Solution and Explanation
PF5 has 5 fluorine atoms bonded to phosphorus, and there are no lone pairs on phosphorus. The electron configuration of phosphorus is 1s² 2s² 2p⁶ 3s² 3p³, and when it forms bonds in PF5, one of its 3s electrons and three of its 3p electrons are used. The hybridization is determined by the number of orbitals involved in bonding, which is four in this case.
The hybridization can be represented as sp³d. The value of y in sp³dy is 1.
Therefore, the value of y is 1.
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.