Comprehension
The Hi-Lo game is a four-player game played in six rounds. In every round, each player chooses to bid Hi or Lo. The bids are made simultaneously. If all four bid Hi, then all four lose 1 point each. If three players bid Hi and one bids Lo, then the players bidding Hi gain 1 point each and the player bidding Lo loses 3 points. If two players bid Hi and two bid Lo, then the players bidding Hi gain 2 points each and the players bidding Lo lose 2 points each. If one player bids Hi and three bid Lo, then the player bidding Hi gains 3 points and the players bidding Lo lose 1 point each. If all four bid Lo, then all four gain 1 point each.
Four players Arun, Bankim, Charu, and Dipak played the Hi-Lo game. The following facts are known about their game:
1.At the end of three rounds, Arun had scored 6 points, Dipak had scored 2 points, Bankim and Charu had scored -2 points each.
2.At the end of six rounds, Arun had scored 7 points, Bankim and Dipak had scored -1 point each, and Charu had scored -5 points.
3.Dipak’s score in the third round was less than his score in the first round but was more than his score in the second round.
4.In exactly two out of the six rounds, Arun was the only player who bid Hi.
Four players Arun, Bankim, Charu, and Dipak played the Hi-Lo game. The following facts are known about their game:
1.At the end of three rounds, Arun had scored 6 points, Dipak had scored 2 points, Bankim and Charu had scored -2 points each.
2.At the end of six rounds, Arun had scored 7 points, Bankim and Dipak had scored -1 point each, and Charu had scored -5 points.
3.Dipak’s score in the third round was less than his score in the first round but was more than his score in the second round.
4.In exactly two out of the six rounds, Arun was the only player who bid Hi.
Question: 1
What were the bids by Arun, Bankim, Charu and Dipak, respectively in the first round?
What were the bids by Arun, Bankim, Charu and Dipak, respectively in the first round?
Updated On: Sep 17, 2024
- Hi, Lo, Lo, Lo
- Lo, Lo, Lo, Hi
- Hi, Hi, Lo, Lo
- Hi, Lo, Lo, Hi
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Lets follow the table :
| R1 | R2 | R3 | T1 | RX | RY | RZ | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | 7 | ||
| B | -2 L | -1 L | 1 L | -2 | -1 L | -1 | ||
| C | -2 L | -1 L | 1 L | -2 | -1 L | -5 | ||
| D | 2 H | -1 L | 1 L | 2 | -1 L | -1 |
Given the conditions for each scenario:
- A: R.x+R.y+R.z=1⇒R.y+R.z=−2
- B: R.x+R.y+R.z=1⇒R.y+R.z=2
- C: R.x+R.y+R.z=−3⇒R.y+R.z=−2
- D: R.x+R.y+R.z=−3⇒R.y+R.z=−2
For scenario A, possible values for (R.y,R.z) are:
- (-3, 1)
- (-1, -1)
Case A1: (𝑅.𝑦,𝑅.𝑧)=(−3,1)(R.y,R.z)=(−3,1)
- Since both C and D require 𝑅.𝑦+𝑅.𝑧=−2R.y+R.z=−2, there are no valid combinations that satisfy all given conditions. Hence, this case is not feasible.
Case A2: (𝑅.𝑦,𝑅.𝑧)=(−1,−1)(R.y,R.z)=(−1,−1)
- For B, C, D, valid combinations are:
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for B: (3, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for C: (-1, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for D: (-1, -1)
Based on these combinations, the bids should be:
- A: (L, H)
- B: (H, H)
- C: (L, H)
- D: (L, H)
This configuration satisfies all the given conditions and is therefore valid.
| R1 | R2 | R3 | T1 | RX | RY | RX | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | -1 L | -1 H | 7 |
| B | -2 L | -1 7 | 1 L | -2 | -1 L | 3 H | 3 H | -1 |
| C | -2 L | -1 L | 1 L | -2 | -1 L | -1 L | -1 H | -5 |
| D | 2 L | -1 L | 1 L | 2 | -1 L | -1 L | -1 H | -1 |
The bids by Arun, Bankim, Charu and Dipak, respectively in the first round are HLLH
So, the correct option is (D): Hi, Lo, Lo, Hi.
Was this answer helpful?
0
0
Question: 2
In how many rounds did Arun bid Hi?
In how many rounds did Arun bid Hi?
Updated On: May 22, 2024
Hide Solution
Verified By Collegedunia
Solution and Explanation
Lets follow the table :
| R1 | R2 | R3 | T1 | RX | RY | RZ | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | 7 | ||
| B | -2 L | -1 L | 1 L | -2 | -1 L | -1 | ||
| C | -2 L | -1 L | 1 L | -2 | -1 L | -5 | ||
| D | 2 H | -1 L | 1 L | 2 | -1 L | -1 |
Given the conditions for each scenario:
- A: R.x+R.y+R.z=1⇒R.y+R.z=−2
- B: R.x+R.y+R.z=1⇒R.y+R.z=2
- C: R.x+R.y+R.z=−3⇒R.y+R.z=−2
- D: R.x+R.y+R.z=−3⇒R.y+R.z=−2
For scenario A, possible values for (R.y,R.z) are:
- (-3, 1)
- (-1, -1)
Case A1: (𝑅.𝑦,𝑅.𝑧)=(−3,1)(R.y,R.z)=(−3,1)
- Since both C and D require 𝑅.𝑦+𝑅.𝑧=−2R.y+R.z=−2, there are no valid combinations that satisfy all given conditions. Hence, this case is not feasible.
Case A2: (𝑅.𝑦,𝑅.𝑧)=(−1,−1)(R.y,R.z)=(−1,−1)
- For B, C, D, valid combinations are:
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for B: (3, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for C: (-1, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for D: (-1, -1)
Based on these combinations, the bids should be:
- A: (L, H)
- B: (H, H)
- C: (L, H)
- D: (L, H)
This configuration satisfies all the given conditions and is therefore valid.
| R1 | R2 | R3 | T1 | RX | RY | RX | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | -1 L | -1 H | 7 |
| B | -2 L | -1 7 | 1 L | -2 | -1 L | 3 H | 3 H | -1 |
| C | -2 L | -1 L | 1 L | -2 | -1 L | -1 L | -1 H | -5 |
| D | 2 L | -1 L | 1 L | 2 | -1 L | -1 L | -1 H | -1 |
Arun bid Hi in R1, R2, R, X, R.z
So, the correct answer is 4.
Was this answer helpful?
0
0
Question: 3
In how many rounds did Bankim bid Lo?
In how many rounds did Bankim bid Lo?
Updated On: May 22, 2024
Hide Solution
Verified By Collegedunia
Solution and Explanation
Lets follow the table :
| R1 | R2 | R3 | T1 | RX | RY | RZ | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | 7 | ||
| B | -2 L | -1 L | 1 L | -2 | -1 L | -1 | ||
| C | -2 L | -1 L | 1 L | -2 | -1 L | -5 | ||
| D | 2 H | -1 L | 1 L | 2 | -1 L | -1 |
Given the conditions for each scenario:
- A: R.x+R.y+R.z=1⇒R.y+R.z=−2
- B: R.x+R.y+R.z=1⇒R.y+R.z=2
- C: R.x+R.y+R.z=−3⇒R.y+R.z=−2
- D: R.x+R.y+R.z=−3⇒R.y+R.z=−2
For scenario A, possible values for (R.y,R.z) are:
- (-3, 1)
- (-1, -1)
Case A1: (𝑅.𝑦,𝑅.𝑧)=(−3,1)(R.y,R.z)=(−3,1)
- Since both C and D require 𝑅.𝑦+𝑅.𝑧=−2R.y+R.z=−2, there are no valid combinations that satisfy all given conditions. Hence, this case is not feasible.
Case A2: (𝑅.𝑦,𝑅.𝑧)=(−1,−1)(R.y,R.z)=(−1,−1)
- For B, C, D, valid combinations are:
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for B: (3, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for C: (-1, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for D: (-1, -1)
Based on these combinations, the bids should be:
- A: (L, H)
- B: (H, H)
- C: (L, H)
- D: (L, H)
This configuration satisfies all the given conditions and is therefore valid.
| R1 | R2 | R3 | T1 | RX | RY | RX | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | -1 L | -1 H | 7 |
| B | -2 L | -1 7 | 1 L | -2 | -1 L | 3 H | 3 H | -1 |
| C | -2 L | -1 L | 1 L | -2 | -1 L | -1 L | -1 H | -5 |
| D | 2 L | -1 L | 1 L | 2 | -1 L | -1 L | -1 H | -1 |
Bikram bid Lo in R1, R2, R3, R. X.
So, the correct answer is 4.
Was this answer helpful?
0
0
Question: 4
In how many rounds did all four players make identical bids?
In how many rounds did all four players make identical bids?
Updated On: May 22, 2024
Hide Solution
Verified By Collegedunia
Solution and Explanation
Lets follow the table :
| R1 | R2 | R3 | T1 | RX | RY | RZ | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | 7 | ||
| B | -2 L | -1 L | 1 L | -2 | -1 L | -1 | ||
| C | -2 L | -1 L | 1 L | -2 | -1 L | -5 | ||
| D | 2 H | -1 L | 1 L | 2 | -1 L | -1 |
Given the conditions for each scenario:
- A: R.x+R.y+R.z=1⇒R.y+R.z=−2
- B: R.x+R.y+R.z=1⇒R.y+R.z=2
- C: R.x+R.y+R.z=−3⇒R.y+R.z=−2
- D: R.x+R.y+R.z=−3⇒R.y+R.z=−2
For scenario A, possible values for (R.y,R.z) are:
- (-3, 1)
- (-1, -1)
Case A1: (𝑅.𝑦,𝑅.𝑧)=(−3,1)(R.y,R.z)=(−3,1)
- Since both C and D require 𝑅.𝑦+𝑅.𝑧=−2R.y+R.z=−2, there are no valid combinations that satisfy all given conditions. Hence, this case is not feasible.
Case A2: (𝑅.𝑦,𝑅.𝑧)=(−1,−1)(R.y,R.z)=(−1,−1)
- For B, C, D, valid combinations are:
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for B: (3, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for C: (-1, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for D: (-1, -1)
Based on these combinations, the bids should be:
- A: (L, H)
- B: (H, H)
- C: (L, H)
- D: (L, H)
This configuration satisfies all the given conditions and is therefore valid.
| R1 | R2 | R3 | T1 | RX | RY | RX | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | -1 L | -1 H | 7 |
| B | -2 L | -1 7 | 1 L | -2 | -1 L | 3 H | 3 H | -1 |
| C | -2 L | -1 L | 1 L | -2 | -1 L | -1 L | -1 H | -5 |
| D | 2 L | -1 L | 1 L | 2 | -1 L | -1 L | -1 H | -1 |
All the players made identical bids in R3 and R.z
So, the correct answer is 2 round.
Was this answer helpful?
0
0
Question: 5
In how many rounds did Dipak gain exactly 1 point?
In how many rounds did Dipak gain exactly 1 point?
Updated On: May 22, 2024
Hide Solution
Verified By Collegedunia
Solution and Explanation
Lets follow the table :
| R1 | R2 | R3 | T1 | RX | RY | RZ | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | 7 | ||
| B | -2 L | -1 L | 1 L | -2 | -1 L | -1 | ||
| C | -2 L | -1 L | 1 L | -2 | -1 L | -5 | ||
| D | 2 H | -1 L | 1 L | 2 | -1 L | -1 |
Given the conditions for each scenario:
- A: R.x+R.y+R.z=1⇒R.y+R.z=−2
- B: R.x+R.y+R.z=1⇒R.y+R.z=2
- C: R.x+R.y+R.z=−3⇒R.y+R.z=−2
- D: R.x+R.y+R.z=−3⇒R.y+R.z=−2
For scenario A, possible values for (R.y,R.z) are:
- (-3, 1)
- (-1, -1)
Case A1: (𝑅.𝑦,𝑅.𝑧)=(−3,1)(R.y,R.z)=(−3,1)
- Since both C and D require 𝑅.𝑦+𝑅.𝑧=−2R.y+R.z=−2, there are no valid combinations that satisfy all given conditions. Hence, this case is not feasible.
Case A2: (𝑅.𝑦,𝑅.𝑧)=(−1,−1)(R.y,R.z)=(−1,−1)
- For B, C, D, valid combinations are:
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for B: (3, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for C: (-1, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for D: (-1, -1)
Based on these combinations, the bids should be:
- A: (L, H)
- B: (H, H)
- C: (L, H)
- D: (L, H)
This configuration satisfies all the given conditions and is therefore valid.
| R1 | R2 | R3 | T1 | RX | RY | RX | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | -1 L | -1 H | 7 |
| B | -2 L | -1 7 | 1 L | -2 | -1 L | 3 H | 3 H | -1 |
| C | -2 L | -1 L | 1 L | -2 | -1 L | -1 L | -1 H | -5 |
| D | 2 L | -1 L | 1 L | 2 | -1 L | -1 L | -1 H | -1 |
Deepak got exactly one point in only R3.
So, the correct answer is 1.
Was this answer helpful?
0
0
Question: 6
In which of the following rounds, was Arun DEFINITELY the only player to bid Hi?
In which of the following rounds, was Arun DEFINITELY the only player to bid Hi?
Updated On: Aug 20, 2024
- First
- Fourth
- Third
- Second
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Lets follow the table :
| R1 | R2 | R3 | T1 | RX | RY | RZ | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | 7 | ||
| B | -2 L | -1 L | 1 L | -2 | -1 L | -1 | ||
| C | -2 L | -1 L | 1 L | -2 | -1 L | -5 | ||
| D | 2 H | -1 L | 1 L | 2 | -1 L | -1 |
Given the conditions for each scenario:
- A: R.x+R.y+R.z=1⇒R.y+R.z=−2
- B: R.x+R.y+R.z=1⇒R.y+R.z=2
- C: R.x+R.y+R.z=−3⇒R.y+R.z=−2
- D: R.x+R.y+R.z=−3⇒R.y+R.z=−2
For scenario A, possible values for (R.y,R.z) are:
- (-3, 1)
- (-1, -1)
Case A1: (𝑅.𝑦,𝑅.𝑧)=(−3,1)(R.y,R.z)=(−3,1)
- Since both C and D require 𝑅.𝑦+𝑅.𝑧=−2R.y+R.z=−2, there are no valid combinations that satisfy all given conditions. Hence, this case is not feasible.
Case A2: (𝑅.𝑦,𝑅.𝑧)=(−1,−1)(R.y,R.z)=(−1,−1)
- For B, C, D, valid combinations are:
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for B: (3, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for C: (-1, -1)
- (𝑅.𝑦,𝑅.𝑧)(R.y,R.z) for D: (-1, -1)
Based on these combinations, the bids should be:
- A: (L, H)
- B: (H, H)
- C: (L, H)
- D: (L, H)
This configuration satisfies all the given conditions and is therefore valid.
| R1 | R2 | R3 | T1 | RX | RY | RX | T2 | |
| A | 2 H | 3 H | 1 L | 6 | 3 H | -1 L | -1 H | 7 |
| B | -2 L | -1 7 | 1 L | -2 | -1 L | 3 H | 3 H | -1 |
| C | -2 L | -1 L | 1 L | -2 | -1 L | -1 L | -1 H | -5 |
| D | 2 L | -1 L | 1 L | 2 | -1 L | -1 L | -1 H | -1 |
R2 is correct answer
So, the correct answer is (D) : Second.
Was this answer helpful?
0
0
Top Questions on Data Analysis
- The figure below shows a network with three parallel roads represented by horizontal lines R-A, R-B, and R-C and another three parallel roads represented by vertical lines V1, V2, and V3. The figure also shows the distance (in km) between two adjacent intersections. Six ATMs are placed at six of the nine road intersections. Each ATM has a distinct integer cash requirement (in Rs. Lakhs), and the numbers at the end of each line in the figure indicate the total cash requirements of all ATMs placed on the corresponding road. For example, the total cash requirement of the ATM(s) placed on road R-A is Rs. 22 Lakhs.
The following additional information is known.
The ATMs with the minimum and maximum cash requirements of Rs. 7 Lakhs and Rs. 15 Lakhs are placed on the same road.
The road distance between the ATM with the second highest cash requirement and the ATM located at the intersection of R-C and V3 is 12 km.
- The two plots below give the following information about six firms A, B, C, D, E, and F for 2019 and 2023.
PAT: The firm’s profits after taxes in Rs. crores,
ES: The firm’s employee strength, that is the number of employees in the firm, and PRD: The percentage of the firm’s PAT that they spend on Research and Development (R&D).
In the plots, the horizontal and vertical coordinates of point representing each firm gives their ES and PAT values respectively. The PRD values of each firm are proportional to the areas around the points representing each firm. The areas are comparable between the two plots, i.e., equal areas in the two plots represent the same PRD values for the two years.
- The numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 are placed in ten slots of the following grid based on the conditions below
1. Numbers in any row appear in an increasing order from left to right.
2. Numbers in any column appear in a decreasing order from top to bottom.
3. 1 is placed either in the same row or in the same column as 10.
4. Neither 2 nor 3 is placed in the same row or in the same column as 10.
5. Neither 7 nor 8 is placed in the same row or in the same column as 9.
6. 4 and 6 are placed in the same row. - Eight gymnastics players numbered 1 through 8 underwent a training camp where they were coached by three coaches - Xena, Yuki, and Zara. Each coach trained at least two players. Yuki trained only even numbered players, while Zara trained only odd numbered players. After the camp, the coaches evaluated the players and gave integer ratings to the respective players trained by them on a scale of 1 to 7, with 1 being the lowest rating and 7 the highest.
The following additional information is known.
1. Xena trained more players than Yuki.
2. Player-1 and Player-4 were trained by the same coach, while the coaches who trained Player-2, Player-3 and Player-5 were all different.
3. Player-5 and Player-7 were trained by the same coach and got the same rating. All other players got a unique rating.
4. The average of the ratings of all the players was 4.
5. Player-2 got the highest rating.
6. The average of the ratings of the players trained by Yuki was twice that of the players trained by Xena and two more than that of the players trained by Zara.
7. Player-4's rating was double of Player-8's and less than Player-5's. - The chart below shows the price data for seven shares – A, B, C, D, E, F, and G as a candlestick plot for a particular day. The vertical axis shows the price of the share in rupees. A share whose closing price (price at the end of the day) is more than its opening price (price at the start of the day) is called a bullish share; otherwise, it is called a bearish share. All bullish and bearish shares are shown in green and red colour respectively.
View More Questions
Questions Asked in CAT exam
- The sum of all real values of $k$ for which $(\frac{1}{8})^k \times (\frac{1}{32768})^{\frac{4}{3}} = \frac{1}{8} \times (\frac{1}{32768})^{\frac{k}{3}}$ is
- CAT - 2024
- Logarithms
- Amal and Vimal together can complete a task in 150 days, while Vimal and Sunil together can complete the same task in 100 days. Amal starts working on the task and works for 75 days, then Vimal takes over and works for 135 days. Finally, Sunil takes over and completes the remaining task in 45 days. If Amal had started the task alone and worked on all days, Vimal had worked on every second day, and Sunil had worked on every third day, then the number of days required to complete the task would have been
- CAT - 2024
- Time and Work
- Gopi marks a price on a product in order to make 20% profit. Ravi gets 10% discount on this marked price, and thus saves Rs 15. Then, the profit, in rupees, made by Gopi by selling the product to Ravi, is
- CAT - 2024
- Profit and Loss
- Sam can complete a job in 20 days when working alone. Mohit is twice as fast as Sam and thrice as fast as Ayana in the same job. They undertake a job with an arrangement where Sam and Mohit work together on the first day, Sam and Ayana on the second day, Mohit and Ayana on the third day, and this three-day pattern is repeated till the work gets completed. Then, the fraction of total work done by Sam is
- CAT - 2024
- Time and Work
- The number of all positive integers up to 500 with non-repeating digits is
- CAT - 2024
- Number Systems
View More Questions