Question:

The function \( f(x) = x^2 + \dfrac{54}{x} \)

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Use the sign of the first derivative to determine increasing/decreasing behavior and extrema.
Updated On: May 15, 2025
  • is increasing and has minimum value 27 in the interval \( (0, \infty) \)
  • is decreasing and has neither maximum nor minimum in the interval \( (-\infty, 0) \)
  • has maximum value 27 in the interval \( (-\infty, 0) \)
  • is increasing and has neither maximum nor minimum values in the interval \( (-\infty, 0) \)
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The Correct Option is B

Solution and Explanation

Given \( f(x) = x^2 + \frac{54}{x} \) Find derivative: \[ f'(x) = 2x - \frac{54}{x^2} \] On the interval \( (-\infty, 0) \), both \( x < 0 \) and \( \frac{1}{x^2}>0 \), hence: \[ f'(x) = 2x - \frac{54}{x^2} < 0 \Rightarrow f(x) \text{ is decreasing} \] Since function keeps decreasing and does not attain a minimum or maximum on \( (-\infty, 0) \), the answer is as given.
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