To solve the problem, we need to determine what factors the focal length of a lens depends on.
1. Formula for Focal Length:
The focal length \( f \) of a lens is given by the lens maker's formula:
\[
\frac{1}{f} = \left( \mu - 1 \right) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)
\]
where \( \mu \) is the refractive index of the lens material, and \( R_1 \) and \( R_2 \) are the radii of curvature of the two spherical surfaces of the lens.
2. Analyzing the Formula:
From the lens maker's formula, we can see that the focal length depends on two factors:
- The **radius of curvature** of the lens surfaces (\( R_1 \) and \( R_2 \)).
- The **refractive index** (\( \mu \)) of the lens material.
3. Conclusion:
Both the radius of curvature and the refractive index of the lens affect its focal length.
Final Answer:
The focal length of a lens depends on both the radius of curvature and the refractive index of the lens, which corresponds to option (C).
Two light beams fall on a transparent material block at point 1 and 2 with angle \( \theta_1 \) and \( \theta_2 \), respectively, as shown in the figure. After refraction, the beams intersect at point 3 which is exactly on the interface at the other end of the block. Given: the distance between 1 and 2, \( d = 4/3 \) cm and \( \theta_1 = \theta_2 = \cos^{-1} \frac{n_2}{2n_1} \), where \( n_2 \) is the refractive index of the block and \( n_1 \) is the refractive index of the outside medium, then the thickness of the block is cm. 