In the following, faculties are referred to by the first letter of their names. Each of MT and ET is assigned 100 marks, with a minimum requirement of at least four questions of 5 marks (4 x 5 = 20), at least three questions of 10 marks (3 x 10 = 30), and at least two questions of 15 marks (2 x 15 = 30). These combine to make up 80 marks. The remaining 20 marks can be distributed among the following possibilities: (Four questions of 5 marks), or (two questions of 10 marks), or (one question of 5 marks and one question of 15 marks), or (two questions of 5 marks and one question of 10 marks). Thus, the total number of questions in MT or ET can be 11, 12, or 13.
Given that ET has more questions than MT, MT has either 11 or 12 questions. However, if MT has 12 questions and ET has 13 questions, or if MT has 11 questions and ET has 12 questions, this condition cannot be satisfied. Therefore, MT has 11 questions (five 5 marks, three 10 marks, and three 15 marks), and ET has 13 questions (eight 5 marks, three 10 marks, and two 15 marks).
This implies that each faculty has contributed four questions in total for MT and ET combined. Since Faculty A has provided only one question in MT, and all other faculties have contributed more than one question, faculties B, C, D, E, and F each have two questions in MT. Consequently, the distribution of questions in MT and ET can be inferred.
In MT, questions 2, 4, and 10 are given by F, C, and D, respectively. Faculty B provides questions 6, 7, and 9 consecutively. The pattern for MT is such that questions 1 to 5 carry 5 marks each, questions 6 to 8 carry 10 marks each, and questions 9 to 11 carry 15 marks each.
In ET, questions 2, 4, 6, 7, 9, 10, 11, and 12 are provided by D, C, A, A, E, B, B, and F, respectively. The distribution of marks in ET is such that questions 1 to 8 carry 8 marks each, questions 9 to 11 carry 10 marks each, and questions 12 and 13 carry 15 marks each.
The second question in ET was prepared by Dave. Ans: (Dave)
In the following, faculties are referred to by the first letter of their names. Each of MT and ET is assigned 100 marks, with a minimum requirement of at least four questions of 5 marks (4 x 5 = 20), at least three questions of 10 marks (3 x 10 = 30), and at least two questions of 15 marks (2 x 15 = 30). These combine to make up 80 marks. The remaining 20 marks can be distributed among the following possibilities: (Four questions of 5 marks), or (two questions of 10 marks), or (one question of 5 marks and one question of 15 marks), or (two questions of 5 marks and one question of 10 marks). Thus, the total number of questions in MT or ET can be 11, 12, or 13.
Given that ET has more questions than MT, MT has either 11 or 12 questions. However, if MT has 12 questions and ET has 13 questions, or if MT has 11 questions and ET has 12 questions, this condition cannot be satisfied. Therefore, MT has 11 questions (five 5 marks, three 10 marks, and three 15 marks), and ET has 13 questions (eight 5 marks, three 10 marks, and two 15 marks).
This implies that each faculty has contributed four questions in total for MT and ET combined. Since Faculty A has provided only one question in MT, and all other faculties have contributed more than one question, faculties B, C, D, E, and F each have two questions in MT. Consequently, the distribution of questions in MT and ET can be inferred.
In MT, questions 2, 4, and 10 are given by F, C, and D, respectively. Faculty B provides questions 6, 7, and 9 consecutively. The pattern for MT is such that questions 1 to 5 carry 5 marks each, questions 6 to 8 carry 10 marks each, and questions 9 to 11 carry 15 marks each.
In ET, questions 2, 4, 6, 7, 9, 10, 11, and 12 are provided by D, C, A, A, E, B, B, and F, respectively. The distribution of marks in ET is such that questions 1 to 8 carry 8 marks each, questions 9 to 11 carry 10 marks each, and questions 12 and 13 carry 15 marks each.
In MT and ET together, there are 13 questions Ans: (13)
In the following, faculties are referred to by the first letter of their names. Each of MT and ET is assigned 100 marks, with a minimum requirement of at least four questions of 5 marks (4 x 5 = 20), at least three questions of 10 marks (3 x 10 = 30), and at least two questions of 15 marks (2 x 15 = 30). These combine to make up 80 marks. The remaining 20 marks can be distributed among the following possibilities: (Four questions of 5 marks), or (two questions of 10 marks), or (one question of 5 marks and one question of 15 marks), or (two questions of 5 marks and one question of 10 marks). Thus, the total number of questions in MT or ET can be 11, 12, or 13.
Given that ET has more questions than MT, MT has either 11 or 12 questions. However, if MT has 12 questions and ET has 13 questions, or if MT has 11 questions and ET has 12 questions, this condition cannot be satisfied. Therefore, MT has 11 questions (five 5 marks, three 10 marks, and three 15 marks), and ET has 13 questions (eight 5 marks, three 10 marks, and two 15 marks).
This implies that each faculty has contributed four questions in total for MT and ET combined. Since Faculty A has provided only one question in MT, and all other faculties have contributed more than one question, faculties B, C, D, E, and F each have two questions in MT. Consequently, the distribution of questions in MT and ET can be inferred.
In MT, questions 2, 4, and 10 are given by F, C, and D, respectively. Faculty B provides questions 6, 7, and 9 consecutively. The pattern for MT is such that questions 1 to 5 carry 5 marks each, questions 6 to 8 carry 10 marks each, and questions 9 to 11 carry 15 marks each.
In ET, questions 2, 4, 6, 7, 9, 10, 11, and 12 are provided by D, C, A, A, E, B, B, and F, respectively. The distribution of marks in ET is such that questions 1 to 8 carry 8 marks each, questions 9 to 11 carry 10 marks each, and questions 12 and 13 carry 15 marks each.
The 15 marks questions in MT and ET are formulated exclusively by Dave, Esha, and Fakir. Answer: (Only Dave, Esha, and Fakir)
In the following, faculties are referred to by the first letter of their names. Each of MT and ET is assigned 100 marks, with a minimum requirement of at least four questions of 5 marks (4 x 5 = 20), at least three questions of 10 marks (3 x 10 = 30), and at least two questions of 15 marks (2 x 15 = 30). These combine to make up 80 marks. The remaining 20 marks can be distributed among the following possibilities: (Four questions of 5 marks), or (two questions of 10 marks), or (one question of 5 marks and one question of 15 marks), or (two questions of 5 marks and one question of 10 marks). Thus, the total number of questions in MT or ET can be 11, 12, or 13.
Given that ET has more questions than MT, MT has either 11 or 12 questions. However, if MT has 12 questions and ET has 13 questions, or if MT has 11 questions and ET has 12 questions, this condition cannot be satisfied. Therefore, MT has 11 questions (five 5 marks, three 10 marks, and three 15 marks), and ET has 13 questions (eight 5 marks, three 10 marks, and two 15 marks).
This implies that each faculty has contributed four questions in total for MT and ET combined. Since Faculty A has provided only one question in MT, and all other faculties have contributed more than one question, faculties B, C, D, E, and F each have two questions in MT. Consequently, the distribution of questions in MT and ET can be inferred.
In MT, questions 2, 4, and 10 are given by F, C, and D, respectively. Faculty B provides questions 6, 7, and 9 consecutively. The pattern for MT is such that questions 1 to 5 carry 5 marks each, questions 6 to 8 carry 10 marks each, and questions 9 to 11 carry 15 marks each.
In ET, questions 2, 4, 6, 7, 9, 10, 11, and 12 are provided by D, C, A, A, E, B, B, and F, respectively. The distribution of marks in ET is such that questions 1 to 8 carry 8 marks each, questions 9 to 11 carry 10 marks each, and questions 12 and 13 carry 15 marks each.
Beti prepared 10thquestion in ET. Ans: (Tenth question)