To find the value of \( m - n \) where \( m \) and \( n \) are natural numbers, \( n > 1 \), and \( m^n = 2^{25} \times 3^{40} \), follow these steps:
- Express \( m \) in terms of prime factors:
\( m = 2^a \times 3^b \) - Substitute \( m \) into the equation:
\( (2^a \times 3^b)^n = 2^{25} \times 3^{40} \) - Apply the power rule for exponents \( (x^m)^n = x^{mn} \):
\( 2^{an} \times 3^{bn} = 2^{25} \times 3^{40} \) - Equate the powers of similar bases:
\( an = 25 \),
\( bn = 40 \) - Solve for \( a \) and \( b \):
\( a = \frac{25}{n} \),
\( b = \frac{40}{n} \) - Since \( a \) and \( b \) must be integers, \( n \) must divide both 25 and 40.
GCD of 25 and 40 is 5, so \( n = 5 \) - Substitute \( n = 5 \) into equations:
\( a = \frac{25}{5} = 5 \),
\( b = \frac{40}{5} = 8 \) - Calculate \( m \):
\( m = 2^5 \times 3^8 = 32 \times 6561 = 209952 \) - Determine \( m - n \):
\( 209952 - 5 = \mathbf{209947} \)
Thus, the value of \( m - n \) is 209947.