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the equation of the tangent to the curve y x 3 2x
Question:
The equation of the tangent to the curve
\[ y = x^3 - 2x + 7 \]
at the point
\( (1,6) \)
is:
Show Hint
To find the equation of a tangent, differentiate the function and use point-slope form.
AP EAPCET - 2024
AP EAPCET
Updated On:
Mar 24, 2025
\( y = x + 5 \)
\( x + y = 7 \)
\( 2x + y = 8 \)
\( x + 2y = 13 \)
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The Correct Option is
A
Solution and Explanation
Step 1: Finding the derivative
\[ \frac{dy}{dx} = 3x^2 - 2. \]
Step 2: Evaluating at \( x = 1 \)
\[ m = 3(1)^2 - 2 = 3 - 2 = 1. \]
Step 3: Using point-slope form
Equation of the tangent: \[ y - 6 = 1(x - 1). \] \[ y = x + 5. \]
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