Question:

The equation of the tangent to the curve \[ y = x^3 - 2x + 7 \] at the point \( (1,6) \) is:

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To find the equation of a tangent, differentiate the function and use point-slope form.
Updated On: Mar 24, 2025
  • \( y = x + 5 \)
  • \( x + y = 7 \)
  • \( 2x + y = 8 \)
  • \( x + 2y = 13 \)
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The Correct Option is A

Solution and Explanation

Step 1: Finding the derivative \[ \frac{dy}{dx} = 3x^2 - 2. \] Step 2: Evaluating at \( x = 1 \) \[ m = 3(1)^2 - 2 = 3 - 2 = 1. \] Step 3: Using point-slope form Equation of the tangent: \[ y - 6 = 1(x - 1). \] \[ y = x + 5. \]
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