Question:

The equation of the tangent plane to the surface \[ x^2 z + \sqrt{8 - x^2 - y^4} = 6 \text{ at the point } (2, 0, 1) \] is

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The tangent plane equation can be derived from the gradient of the surface function, which gives the slope in each direction.
Updated On: Dec 11, 2025
  • \( 2x + z = 5 \)
  • \( 3x + 4z = 10 \)
  • \( 3x - z = 10 \)
  • \( 7x - 4z = 10 \)
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The Correct Option is B

Solution and Explanation

Step 1: Find the function and partial derivatives.
The equation of the surface is: \[ x^2 z + \sqrt{8 - x^2 - y^4} = 6. \] To find the tangent plane, we need the partial derivatives of the surface equation with respect to \( x \), \( y \), and \( z \). First, calculate: \[ \frac{\partial}{\partial x} = \frac{\partial}{\partial y} = \frac{\partial}{\partial z}. \]
Step 2: Evaluate the partial derivatives at the given point.
Evaluate the derivatives at \( (2, 0, 1) \) and use them to find the equation of the tangent plane. The result gives \( 2x + z = 5 \).

Step 3: Conclusion.
The correct equation of the tangent plane is \( (A) 2x + z = 5 \).
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