Question:

Let \( f(x) = 10x^2 + e^x - \sin(2x) - \cos x \), \( x \in \mathbb{R} \). The number of points at which the function \( f \) has a local minimum is:

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To find the local minima of a function, first solve for the critical points using \( f'(x) = 0 \), then use the second derivative test to classify the critical points.
Updated On: Sep 6, 2025
  • 0
  • 1
  • 2
  • greater than or equal to 3
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The Correct Option is B

Solution and Explanation

Step 1: Find the first derivative of \( f(x) \).
\[ f'(x) = 20x + e^x - 2\cos(2x) + \sin x \] We set \( f'(x) = 0 \) to find the critical points. Step 2: Analyze the second derivative.
The second derivative is: \[ f''(x) = 20 + e^x + 4\sin(2x) + \cos x \] To find the points where \( f(x) \) has a local minimum, check where \( f''(x)>0 \). Step 3: Conclusion.
By solving these equations and analyzing the second derivative, we conclude that \( f(x) \) has 1 point of local minimum. Final Answer: \[ \boxed{1} \]
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