1. Understand the problem:
We need to find the equation of a parabola given its focus at (6, 0) and directrix \( x = -6 \).
2. Recall the definition of a parabola:
A parabola is the locus of points equidistant from the focus and the directrix.
3. Let \( (x, y) \) be any point on the parabola:
The distance from \( (x, y) \) to the focus (6, 0) is:
\[ \sqrt{(x - 6)^2 + (y - 0)^2} \]
The distance from \( (x, y) \) to the directrix \( x = -6 \) is:
\[ |x + 6| \]
4. Set the distances equal and simplify:
\[ \sqrt{(x - 6)^2 + y^2} = |x + 6| \]
Square both sides to eliminate the square root and absolute value:
\[ (x - 6)^2 + y^2 = (x + 6)^2 \]
Expand both sides:
\[ x^2 - 12x + 36 + y^2 = x^2 + 12x + 36 \]
Simplify by canceling \( x^2 \) and 36 from both sides:
\[ -12x + y^2 = 12x \]
Combine like terms:
\[ y^2 = 24x \]
Correct Answer: (A) \( y^2 = 24x \)
The definition of a parabola is the set of all points equidistant from the focus and the directrix.
Let \( (x, y) \) be a point on the parabola.
The distance from \( (x, y) \) to the focus \( (6, 0) \) is:
The distance from \( (x, y) \) to the directrix \( x = -6 \) is:
\[ |x + 6| \]Since these distances are equal:
\[ \sqrt{(x - 6)^2 + y^2} = |x + 6| \]Square both sides:
\[ (x - 6)^2 + y^2 = (x + 6)^2 \] \[ x^2 - 12x + 36 + y^2 = x^2 + 12x + 36 \] \[ y^2 = 24x \]Therefore, the equation of the parabola is \( y^2 = 24x \).
Two parabolas have the same focus $(4, 3)$ and their directrices are the $x$-axis and the $y$-axis, respectively. If these parabolas intersect at the points $A$ and $B$, then $(AB)^2$ is equal to:
In an experiment to determine the figure of merit of a galvanometer by half deflection method, a student constructed the following circuit. He applied a resistance of \( 520 \, \Omega \) in \( R \). When \( K_1 \) is closed and \( K_2 \) is open, the deflection observed in the galvanometer is 20 div. When \( K_1 \) is also closed and a resistance of \( 90 \, \Omega \) is removed in \( S \), the deflection becomes 13 div. The resistance of galvanometer is nearly:
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is