We are asked to form four-digit even numbers using the digits 0, 1, 2, and 3 without repetition.
- The first digit cannot be 0 (since it would not be a four-digit number), so the first digit can be 1, 2, or 3. This gives us 3 choices for the first digit.
- The last digit must be even, so the last digit can be 0 or 2. Therefore, we have 2 choices for the last digit.
- After selecting the first and last digits, we are left with 2 digits from the remaining available digits. So, for the second digit, we have 2 choices, and for the third digit, we have 1 choice.
Thus, the total number of possible four-digit even numbers is:
3 × 2 × 2 × 1 = 6
So, the correct answer is 6.
The number of 6-letter words, with or without meaning, that can be formed using the letters of the word MATHS such that any letter that appears in the word must appear at least twice, is $ 4 \_\_\_\_\_$.
Match List-I with List-II and select the correct option: 