Question:

The enthalpy of vaporisation of a substance is 8400 J mol1 and its boiling point is 173.15C. The entropy change for vaporisation is:

Updated On: Sep 30, 2024
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Correct Answer: 84

Solution and Explanation

Explanation:
Given: Enthalpy of vaporisation of a substance is: 8400 J mol1Temperature or boiling point of substance is: 173.15C We have temperature in Kelvin,= Celsius temperature +273.15C=173.15C+273.15C=100 KNow, we know,Change in entropy, ΔS=qrevT=(8400100)=84 Jmol1K1 Hence, the correct answer is '84'.
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