Question:
The elements of Group 13 with highest and lowest first ionisation enthalpies are respectively:
The elements of Group 13 with highest and lowest first ionisation enthalpies are respectively:
Show Hint
Ionisation enthalpy decreases down the group because of increasing atomic size and electron shielding.
Updated On: Apr 23, 2025
B & Ga
B & Tl
Ti & B
B & In
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
- The ionisation enthalpy decreases as we move down a group.
Boron (B) has the highest ionisation enthalpy in Group 13, while Gallium (Ga) has the lowest due to the larger atomic radius and shielding effect as we move down the group.
Thus, the correct answer is (1).
Was this answer helpful?
0
0
Top Questions on Periodic Trends In Properties Of Elements
- Which of the following statements is not correct?
- AP EAPCET - 2025
- Chemistry
- Periodic Trends In Properties Of Elements
- Identify the correct statements from the following:
I) CO reduces the oxygen carrying ability of blood.
II) Producer gas contains CO and N₂.
III) C-O bond length in CO₂ is 115 pm.- AP EAPCET - 2025
- Chemistry
- Periodic Trends In Properties Of Elements
- Which of the following properties is not correct for silicones?
- AP EAPCET - 2025
- Chemistry
- Periodic Trends In Properties Of Elements
- Identify the incorrect order against the stated property.
- AP EAPCET - 2025
- Chemistry
- Periodic Trends In Properties Of Elements
- Which of the following properties is not correct for silicones?
- AP EAPCET - 2025
- Chemistry
- Periodic Trends In Properties Of Elements
View More Questions
Questions Asked in JEE Main exam
- If \( \alpha + i\beta \) and \( \gamma + i\delta \) are the roots of the equation \( x^2 - (3-2i)x - (2i-2) = 0 \), \( i = \sqrt{-1} \), then \( \alpha\gamma + \beta\delta \) is equal to:
- JEE Main - 2025
- Complex numbers
- If \( \alpha \) and \( \beta \) are the roots of the equation \( 2z^2 - 3z - 2i = 0 \), where \( i = \sqrt{-1} \), then \[ 16 \cdot {Re} \left( \frac{\alpha^{19} + \beta^{19} + \alpha^{11} + \beta^{11}}{\alpha^{15} + \beta^{15}} \right) \cdot {Im} \left( \frac{\alpha^{19} + \beta^{19} + \alpha^{11} + \beta^{11}}{\alpha^{15} + \beta^{15}} \right) \] is equal to:
- JEE Main - 2025
- Complex numbers
Statement-1: \( \text{ClF}_3 \) has 3 possible structures.
Statement-2: \( \text{III} \) is the most stable structure due to least lone pair-bond pair (lp-bp) repulsion.
Which of the following options is correct?
- JEE Main - 2025
- Molecular Stability
- If the image of the point $ P(1, 0, 3) $ in the line joining the points $ A(4, 7, 1) $ and $ B(3, 5, 3) $ is $ Q(\alpha, \beta, \gamma) $, then $ \alpha + \beta + \gamma $ is equal to:
- JEE Main - 2025
- 3D Geometry
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is:
- JEE Main - 2025
- Number Systems
View More Questions