The electrostatic potential due to an electric dipole at a distance \( r \) varies as:
Show Hint
The electric potential due to a monopole (point charge) follows a \( \frac{1}{r} \) relationship, whereas for a dipole, the potential decreases with the square of the distance, \( \frac{1}{r^2} \).
The electrostatic potential \( V_p \) at a point at distance \( r \) from the center of an electric dipole is inversely proportional to the square of the distance:
\[
V_p \propto \frac{1}{r^2}.
\]
This is because the potential due to a dipole decreases at a faster rate compared to a point charge, which follows the \( \frac{1}{r} \) dependence. In a dipole, the opposing charges create a field that reduces more sharply with distance.
Final Answer:
\[
\boxed{\frac{1}{r^2}}.
\]