Question:

The electrostatic force (\( \vec{F_1} \)) and magnetic force (\( \vec{F_2} \)) acting on a charge \( q \) moving with velocity \( \vec{v} \) can be written:

Updated On: Nov 26, 2024
  • \( \vec{F_1} = q \vec{V} \cdot \vec{E}, \quad \vec{F_2} = q (\vec{B} \cdot \vec{V}) \)
  • \( \vec{F_1} = q \vec{B}, \quad \vec{F_2} = q (\vec{B} \times \vec{V}) \)
  • \( \vec{F_1} = q \vec{E}, \quad \vec{F_2} = q (\vec{V} \times \vec{B}) \)
  • \( \vec{F_1} = q \vec{E}, \quad \vec{F_2} = q (\vec{B} \times \vec{V}) \)
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The Correct Option is C

Solution and Explanation

The electrostatic force acting on a charged particle is given by:

\[ \vec{F}_1 = q\vec{E}, \]

where:
- \( q \) is the charge of the particle,
- \( \vec{E} \) is the electric field.

The magnetic force acting on a charged particle moving with velocity \( \vec{v} \) in a magnetic field \( \vec{B} \) is given by the Lorentz force law:

\[ \vec{F}_2 = q(\vec{v} \times \vec{B}), \]

where:
- \( q \) is the charge of the particle,
- \( \vec{v} \) is the velocity of the particle,
- \( \vec{B} \) is the magnetic field.

Therefore, the correct expressions for the electrostatic and magnetic forces are:

\[ \vec{F}_1 = q\vec{E}, \quad \vec{F}_2 = q(\vec{v} \times \vec{B}). \]

Hence, the correct option is (3).

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