Question:

The electrostatic force (F1 \vec{F_1} ) and magnetic force (F2 \vec{F_2} ) acting on a charge q q moving with velocity v \vec{v} can be written:

Updated On: Mar 22, 2025
  • F1=qVE,F2=q(BV) \vec{F_1} = q \vec{V} \cdot \vec{E}, \quad \vec{F_2} = q (\vec{B} \cdot \vec{V})
  • F1=qB,F2=q(B×V) \vec{F_1} = q \vec{B}, \quad \vec{F_2} = q (\vec{B} \times \vec{V})
  • F1=qE,F2=q(V×B) \vec{F_1} = q \vec{E}, \quad \vec{F_2} = q (\vec{V} \times \vec{B})
  • F1=qE,F2=q(B×V) \vec{F_1} = q \vec{E}, \quad \vec{F_2} = q (\vec{B} \times \vec{V})
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The Correct Option is C

Solution and Explanation

The electrostatic force acting on a charged particle is given by:

F1=qE, \vec{F}_1 = q\vec{E},

where:
- q q is the charge of the particle,
- E \vec{E} is the electric field.

The magnetic force acting on a charged particle moving with velocity v \vec{v} in a magnetic field B \vec{B} is given by the Lorentz force law:

F2=q(v×B), \vec{F}_2 = q(\vec{v} \times \vec{B}),

where:
- q q is the charge of the particle,
- v \vec{v} is the velocity of the particle,
- B \vec{B} is the magnetic field.

Therefore, the correct expressions for the electrostatic and magnetic forces are:

F1=qE,F2=q(v×B). \vec{F}_1 = q\vec{E}, \quad \vec{F}_2 = q(\vec{v} \times \vec{B}).

Hence, the correct option is (3).

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