Question:

The electronegativities of $C, N, Si$ and $P$ are in the order of

Updated On: Feb 23, 2024
  • $P < Si < C < N$
  • $Si < P < N < C$
  • $Si < P < C < N$
  • $P < Si < N < C$
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The Correct Option is C

Solution and Explanation

Electronegativity increases as we more left to right in a period and decreases as we move down in the group. (i) $C$ and $N$ belong to the same period. Hence $N$ has more electronegativity than carbon (C). (ii) In the same way $P$ is more electronegative than Si (iii) As Si is below the carbon is 14th group the electronegativity of carbons is more than of Si.
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Concepts Used:

Classification of Elements & Periodicity in Properties

Since many elements were being discovered in the 19th century and the study of these elements individually was proving difficult, classification of elements was made necessary.

Classification by Johann Dobereiner - German chemist Johann Dobereiner classified certain elements on the basis of their similar properties in the groups of continuing - three elements each. These groups were called ‘triads’. In every triad, the atomic weight of the middle element was equal to the average of the atomic weights of the first and third elements. 

Newlands Law of Octaves - The elements were arranged in increasing order of their atomic weights and found that every 8th element shows similarity with the 1st element. 

Mendeleev’s Periodic Table - The arrangement of all 63 elements in rows or columns in order of their atomic weight was made by Mendeleev. He left some space for corresponding elements in his periodic table which were not even discovered till then. Although he predicted the properties of those elements through his periodic classification of elements. 

Modern Periodic Law - The properties of the elements of the modern periodic law are periodic functions of their atomic numbers.