To understand what \( \left( \frac{\alpha}{\beta} \right) \) represents in the equation for electric flux \( \varphi = \alpha \sigma + \beta \lambda \), we need to analyze the physical dimensions and properties involved.
Electric flux \( \varphi \) relates to the surface covered by an electric field and is typically calculated as the dot product of the electric field \( E \) and area \( A \), expressed as \( \varphi = E \cdot A \), implying that electric flux has dimensions of an electric field times an area.
In the given equation \( \varphi = \alpha \sigma + \beta \lambda \):
The coefficients \( \alpha \) and \( \beta \) must have dimensions that, when multiplied by their respective charge densities, result in the dimensions of electric flux \([E][A]\).
Let's analyze:
For the term \( \alpha \sigma \):
For the term \( \beta \lambda \):
Now, compute the ratio \( \frac{\alpha}{\beta} \):
Thus, the ratio \( \frac{\alpha}{\beta} \) represents a physical quantity with dimensions of length, typically associated with displacement in physics. Therefore, the correct interpretation of \( \left( \frac{\alpha}{\beta} \right) \) in this context is displacement.
Refer to the circuit diagram given in the figure, which of the following observations are correct?
Observations:
A. Total resistance of circuit is 6 Ω
B. Current in Ammeter is 1 A
C. Potential across AB is 4 Volts
D. Potential across CD is 4 Volts
E. Total resistance of the circuit is 8 Ω
Choose the correct answer from the options given below: