Question

The efficiency of Carnot’s engine working between the steam point and the ice point is:

• A. 0.268
• B. 0.0268
• C. 0.628
• D. 0.826

Hint:

Always convert Celsius to Kelvin in thermodynamics. Carnot efficiency = (TH −TL)/TH.

Answer 1

The Correct Option is A

Steam point $= 100^\circ\text{C} = 373 \text{ K}$.
Ice point $= 0^\circ\text{C} = 273 \text{ K}$.
Carnot Efficiency, $\eta = \frac{T_H - T_L}{T_H} = \frac{373-273}{373} = \frac{100}{373} \approx 0.268 \approx 26.8\%$.