The following table shows the total number of people who were stuck in traffic jam while going to their office on working days of a week due to construction of a flyover. Table also shows the ratio of male to female among them. If 30% males on Tuesday and 60% males on Wednesday reached their office on regular time of the office, then how many males got late on Tuesday and Wednesday taken together?
Show Hint
Multi-step data interpretation problems require careful calculation at each stage. A small error in an early step (like calculating the number of males) will lead to an incorrect final answer. Always double-check your intermediate results.
Step 1: Calculate the number of males stuck in traffic on Tuesday.
- Total people on Tuesday = 4800.
- Ratio of Male:Female = 1:5. Total parts = 1+5=6.
- Number of males on Tuesday = \( 4800 \times \frac{1}{6} = 800 \).
Step 2: Calculate the number of males who got late on Tuesday.
- 30% of males reached on time. This means \(100% - 30% = 70%\) got late.
- Late males on Tuesday = \( 800 \times 0.70 = 560 \).
Step 3: Calculate the number of males stuck in traffic on Wednesday.
- Total people on Wednesday = 5000.
- Ratio of Male:Female = 3:7. Total parts = 3+7=10.
- Number of males on Wednesday = \( 5000 \times \frac{3}{10} = 1500 \).
Step 4: Calculate the number of males who got late on Wednesday.
- 60% of males reached on time. This means \(100% - 60% = 40%\) got late.
- Late males on Wednesday = \( 1500 \times 0.40 = 600 \). No, wait. 1504 = 600. Let me recheck.
- Let me re-read the values. Wednesday M:F = 3:7. Males = 1500. 60% on time \textrightarrow 40% late. 1500 0.4 = 600. This is correct.
Let me try Q66 again with a clear head.
Tuesday: Total 4800, M:F=1:5. Males=800. 30% on time \textrightarrow 70% late. Late = 800 0.7 = 560.
Wednesday: Total 5000, M:F=3:7. Males=1500. 60% on time \textrightarrow 40% late. Late = 1500 0.4 = 600.
Total late males = 560 + 600 = 1160.
This doesn't match any option. Let me re-read the table. Tuesday M:F is 1:5. Wednesday M:F is 3:7. The numbers seem correct.
Could the percentages be of the total people? No, it says "30% males".
Let me recheck the calculation. 800 0.7 = 560. 1500 0.4 = 600. Sum = 1160.
Maybe I read the table wrong.
Monday: 6300, 3:4
Tuesday: 4800, 1:5
Wednesday: 5000, 3:7
Thursday: 2500, 2:3
Friday: 5400, 4:5
The values are correct. The calculations seem correct. Let's re-read the question. "how many males got late". The steps are correct.
Let's assume the question meant "females".
Tuesday Females = 4000. Late = 4000 0.7 = 2800.
Wednesday Females = 3500. Late = 3500 0.4 = 1400. Sum = 4200. No.
Let's assume the percentage is who got late.
Late males Tue = 800 0.3 = 240.
Late males Wed = 1500 0.6 = 900.
Total = 240 + 900 = 1140. Still not matching.
There must be an error in the question data or the options. Let's try to work backwards from option A, 1290.
If Total Late = 1290, and Wed Late = 600, then Tue Late must be 1290-600=690.
For Tue Late to be 690, if 70% were late, Total Males = 690/0.7 = 985.7. Not an integer.
If 30% were late, Total Males = 690/0.3 = 2300. Not 800.
The question is likely flawed.
