Question:

The determinant of a 3 × 3 matrix \( M \) is 8. If every element of \( M \) is multiplied by \( -2 \), the determinant of the modified matrix will be:

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When scaling all elements of a matrix by a constant \( k \), the determinant is scaled by \( k^n \), where \( n \) is the order of the matrix.
Updated On: Apr 14, 2025
  • −64
  • −16
  • 8
  • 64
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The Correct Option is A

Solution and Explanation

Concept:
When every element of a matrix is multiplied by a constant \( k \), the determinant of the matrix is multiplied by \( k^n \), where \( n \) is the order (size) of the square matrix.

Given:
The matrix is of order \( 3 \times 3 \), and the original determinant is \( 8 \).
Each element is multiplied by \( -2 \).

Step-by-step Calculation:
Since it's a 3 × 3 matrix, the new determinant becomes: \[ \text{New Determinant} = (-2)^3 \times 8 = -8 \times 8 = -64 \]
✔️ Final Answer: The determinant of the modified matrix is \( -64 \).
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