Question

The depletion region in a semiconductor is created by:

• A. Ionization only
• B. Diffusion only
• C. Recombination only
• D. All three: ionization, diffusion, and recombination

Answer 1

The Correct Option is D

The depletion region in a semiconductor is formed due to a combination of three processes: ionization, diffusion, and recombination. Let’s analyze these processes:

1. Ionization:

In an intrinsic semiconductor, when an external electric field is applied or a voltage is applied across the junction, the atoms in the semiconductor can undergo ionization. This process leads to the creation of free electrons and holes, which contributes to the formation of a depletion region.

2. Diffusion:

In the case of a P-N junction, when the P-type and N-type semiconductors come into contact, free electrons from the N-region diffuse into the P-region, and holes from the P-region diffuse into the N-region. This diffusion causes the region near the junction to become depleted of charge carriers, forming the depletion region.

3. Recombination:

As the free electrons and holes diffuse into each other, they recombine. The recombination of electrons and holes in the vicinity of the junction further depletes the region of free charge carriers, strengthening the depletion region.

Conclusion: The depletion region in a semiconductor is created by all three processes: ionization, diffusion, and recombination. These processes work together to establish the electrically neutral zone known as the depletion region, which is crucial for the functioning of semiconductor devices like diodes and transistors.