The density of nitric acid solution is 1.5 g mL\(^{-1}\). Its weight percentage is 68. What is the approximate concentration (in mol L\(^{-1}\)) of nitric acid? (N = 14 u; O = 16 u; H = 1 u)
The density of the nitric acid solution is given as 1.5 g/mL, with a weight percentage of 68% HNO\(_3\). Our task is to find the molar concentration in mol/L.
First, calculate the mass of HNO\(_3\) in 1 L (1000 mL) of solution:
\( \text{Mass of solution} = \text{density} \times \text{volume} = 1.5 \, \text{g/mL} \times 1000 \, \text{mL} = 1500 \, \text{g} \)
\( \text{Mass of HNO}_3 = 0.68 \times 1500 \, \text{g} = 1020 \, \text{g} \)
Given: Molar mass of HNO\(_3\):
\( \text{Molar mass of HNO}_3 = (1 \times 1) + (1 \times 14) + (3 \times 16) = 63 \, \text{g/mol} \)
Calculate the number of moles of HNO\(_3\):
\( \text{Moles of HNO}_3 = \frac{1020 \, \text{g}}{63 \, \text{g/mol}} = 16.190 \, \text{mol} \)
Calculate the concentration in mol/L:
\( \text{Concentration} = \frac{\text{Moles of HNO}_3}{\text{Volume in L}} = \frac{16.190 \, \text{mol}}{1 \, \text{L}} \approx 16.2 \, \text{mol/L} \)
Thus, the approximate concentration of nitric acid is \(16.2 \, \text{mol/L}\).
Here's how to calculate the concentration:
Therefore, the approximate concentration of nitric acid is 16.2 mol L−1.
Quantitative analysis of an organic compound (X) shows the following percentage composition.
C: 14.5%
Cl: 64.46%
H: 1.8%
Empirical formula mass of the compound (X) is: