1. Calculate millimoles of NaOH:
\[ \text{Millimoles of NaOH} = 0.24 \times 25 = 6 \, \text{mmol}. \]
2. Since the acid is monobasic, millimoles of acid required = millimoles of NaOH = 6 mmol.
3. Mass of acid required:
\[ \text{Mass of acid} = 6 \times 24.2 = 145.2 \, \text{mg}. \]
4. Volume of acid solution:
Using \(\text{Volume} = \frac{\text{mass}}{\text{density}}\),
\[ V = \frac{145.2}{1.21 \times 10^3} = 0.12 \, \text{mL}. \]
5. Convert to \(10^{-3}\):
\[ V = 12 \times 10^{-3} \, \text{mL}. \]
Thus, the volume required is 12 \(\times\) \(10^{-3} mL\).
Neutralization of a monobasic acid requires equal millimoles of acid and base. Use the density of the acid solution to calculate the required volume.


Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
Which of the following best represents the temperature versus heat supplied graph for water, in the range of \(-20^\circ\text{C}\) to \(120^\circ\text{C}\)? 
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