The decreasing order of stability of the following carbocations is:
\( (i) \text{(CH}_3\text{)}_3\text{C}^+ \quad (ii) \text{(CH}_3\text{)}_2\text{C-CH}_2^+ \quad (iii) \text{CH}_3\text{CH}_2\text{-CH}_2^+ \)
The decreasing order of stability of the following carbocations is:
\( (i) \text{(CH}_3\text{)}_3\text{C}^+ \quad (ii) \text{(CH}_3\text{)}_2\text{C-CH}_2^+ \quad (iii) \text{CH}_3\text{CH}_2\text{-CH}_2^+ \)
Show Hint
- \( (i)>(ii)>(iii) \)
- \( (ii)>(i)>(iii) \)
- \( (iii)>(ii)>(i) \)
- \( (i)>(iii)>(ii) \)
- \( (i)>(ii)>(iii) \)
The Correct Option is D
Solution and Explanation
Carbocation stability follows the order tertiary > secondary > primary due to hyperconjugation and inductive effects.
- Tertiary carbocation \((i)\) is the most stable due to maximum hyperconjugation from three methyl groups.
- Primary carbocation \((iii)\) is more stable than the secondary carbocation \((ii)\) due to its structure.
- Secondary carbocation \((ii)\) is the least stable due to minimal hyperconjugation.
Thus, the correct order is: \[ {(i) > (iii) > (ii)} \]
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