Question

The current through a \(\frac{4}{3}\Omega\) external resistance connected to a parallel combinationof two cells of 2 V and 1 V emf and internal resistances of 1 \(\Omega\) and 2 \(\Omega\) respectively is ______.
Fill in the blank with the correct answer from the options given below

• A. 1A
• B. \(\frac{2}{3}A\)
• C. \(\frac{3}{4}A\)
• D. \(\frac{5}{6}A\)

Answer 1

The Correct Option is D

The total emf of the combination of cells in parallel is given by Substituting the given values, we find the total emf and internal resistance. Then, the current is calculated using Ohm’s law \(\frac{E_{total}}{R_{total}}=\frac{E_1}{r_1}+\frac{E_2}{r_2}\) \(I = \frac{E_{\text{total}}}{R_{\text{total}} + R_{\text{external}}}\)