To identify- and-anomers, check the orientation of the-OH group on the anomeric carbon. In-anomers, it points downward, while in-anomers, it points upward
Sugar [X] is D-glucose, which can cyclize to form a six-membered pyranose ring. The structure depends on the orientation of the -OH group on the anomeric carbon (C-1):
Conclusion: Since the question asks for the β-D-glucopyranose form, Diagram 1 is the correct representation.
Assume a living cell with 0.9% (\(w/w\)) of glucose solution (aqueous). This cell is immersed in another solution having equal mole fraction of glucose and water. (Consider the data up to first decimal place only) The cell will:
Identify correct conversion during acidic hydrolysis from the following:
(A) Starch gives galactose.
(B) Cane sugar gives equal amount of glucose and fructose.
(C) Milk sugar gives glucose and galactose.
(D) Amylopectin gives glucose and fructose.
(E) Amylose gives only glucose.
Choose the correct answer from the options given below:
Biomolecules are the most essential organic molecules, which are involved in the maintenance and metabolic processes of living organisms. These non-living molecules are the actual foot-soldiers of the battle of sustenance of life.
There are four major classes of Biomolecules – Carbohydrates, Proteins, Nucleic acids and Lipids.