Question:

The correct order of the spin-only magnetic moment of metal ions in the following low spin complexes, [V(CN)6]4,[Fe(CN)6]4,[Ru(NH3)6]3+,{[V(CN)_6]^{4-}, [Fe(CN)6]^{4-}, [Ru (NH3)6]^{3+},} and [Cr(NH3)6]2+{[Cr(NH3)6]^{2+}}, is :

Updated On: Sep 30, 2024
  • V2+>Cr2+>Ru3+>Fe2+{V^{2+} > Cr^{2+} > Ru^{3+} > Fe^{2+}}
  • V2+>Ru3+>Cr2+>Fe2+{V^{2+} > Ru^{3+} > Cr^{2+}> Fe^{2+}}
  • Cr2+>V2+>Ru3+>Fe2+{Cr^{2+} > V^{2+} > Ru^{3+} > Fe^{2+}}
  • Cr2+>Ru3+>Fe2+>V2+{ Cr^{2+} > Ru^{3+} > Fe^{2+} > V^{2+} }
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Solution:- (A)V2+>Cr2+>Ru3+>Fe2+( A ) V ^{2+}> Cr ^{2+}> Ru ^{3+}> F e ^{2+}
According to equations, all the complexes are low spin. No. of Complex \quad Configuration unpaired electrons [[V(CN)6]4t2g3eg03\left[\begin{array}{lll}{\left[ V ( CN )_{6}\right]^{4-}} & t _{2 g }^{3} e _{ g }^{0} & 3\end{array}\right.
No. ot Complex Configuration unpaired electrons [V(CN)6]4t2g3eg0\left[ V ( C N )_{6}\right]^{4-} \quad t _{ 2 g }^{3} e _{ g }^{0}
3
[Cr(NH)3)6]2+t2g4eg0\left.\left[ C r ( N H )_{3}\right)_{6}\right]^{2+} t _{2 g }^{4} e _{ g }^{0}
2
[Ru(NH3)6]3+t2g5eg0\left[ R u \left( N H _{3}\right)_{6}\right]^{3+} t _{2 g }^{5} e _{ g }^{0}
1
[Fe(CN)6]4t2g6eg0\left[ F e ( C N )_{6}\right]^{4-} t _{2 g }^{6} e _{ g }^{0}
0
Was this answer helpful?
1
0

Questions Asked in JEE Main exam

View More Questions

Concepts Used:

Properties of D Block Elements

  • Multiple oxidation states- The oxidation states of d block elements show very few energy gaps; therefore, they exhibit many oxidation states. Also, the energy difference between s and d orbital is very less. Therefore both the electrons are involved in ionic and covalent bond formation, which ultimately leads to multiple oxidation states.
  • Formation of complex compounds- Ligands show a binding behavior and can form so many stable complexes with the help of transition metals. This property is mainly due to:
    • Availability of vacant d orbitals.
    • Comparatively small sizes of metals.
  • Hardness- Transition elements are tough and have high densities because of the presence of unpaired electrons.
  • Melting and boiling points- Melting and boiling points of transition are very high because of the presence of unpaired electrons and partially filled d orbitals. They form strong bonds and have high melting and boiling points.
  • Atomic radii- The atomic and ionic radius of the transition elements decreases as we move from Group 3 to group 6. However, it remains the same between group 7 and group 10, and from group 11 to group 12 increases.
  • Ionization enthalpy- The ionization enthalpies of the transition elements are generally on the greater side as compared to the S block elements